C++

1/**
2 * Runtime: 4 ms, faster than 66.67%
3 * Memory Usage: 11.8 MB, less than 33.33%
4 */
5class Solution {
6  public:
7    bool arrayStringsAreEqual(vector<string>& word1, vector<string>& word2) {
8      string str1 = "";
9      string str2 = "";
10
11      for (string s : word1) 
12        str1 += s;
13
14      for (string s : word2) 
15        str2 += s;
16
17      if (str1.size() != str2.size()) 
18        return false;
19      else
20      {    
21        for (int i=0; i<str1.size(); ++i)
22        {
23          if (str1[i] != str2[i])
24            return false;
25        }
26      }
27
28      return true;
29    }
30};

JavaScript

1/**
2 * Runtime: 84 ms, faster than 100.00%
3 * Memory Usage: 38.8 MB, less than 100.00%
4 */
5var arrayStringsAreEqual = function(word1, word2) {
6  let str1 = word1.join('');
7  let str2 = word2.join('');
8
9  if (str1.length != str2.length) {
10    return false;
11  }
12
13  for (let i=0; i<str1.length; ++i) {
14    if (str1[i] != str2[i])
15      return false;
16  }
17
18  return true;
19};

Ruby

1# Runtime: 48 ms, faster than 100.00%
2# Memory Usage: 210 MB, less than 100.00%
3def array_strings_are_equal(word1, word2)
4  str1 = word1.join
5  str2 = word2.join
6
7  return false if str1.size != str2.size
8
9  for i in (0...str1.size) do
10    return false if str1[i] != str2[i] 
11  end
12
13  true
14end